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From time to time, our visitors submit riddles to us. On this page, we will publish them as we get them. If the answers are submitted, they are included here. 
By the way, the answer to the "GRY" riddle can be found by clicking here!*
AND, the answer to the missing dollar riddle is here!
Is your riddle HERE??? Tell a friend about it --

here is a riddle i found on the internet..im not sure if this is appropriate for your page but i thought it was very cool

God made Adam out of the dust,

But thought it best to make me first;

So I was made before the man,

According to God's Holy plan.

My whole body God made complete,

Without arms or hands or feet.

My ways and acts did God control,

But in my body He placed no soul.

A living being I became,

And Adam gave to me a name.

Then from his presence I withdrew,

For this man Adam I never knew.

All my Maker's laws I do obey,

And from these laws I never stray.

Thousands of me go in fear,

But seldom on the earth appear.

Later, for a purpose God did see,

He placed a living soul in me.

But that soul of mine God had to claim,

And from me took it back again.

And when this soul from me had fled,

I was the same as when first made;

Without arms, legs, feet, or soul,

I travel on from pole to pole.

My labors are from day to night,

And to men I once furnished light.

Thousands of people both young and old,

Did by my death bright lights behold.

No right or wrong can I conceive;

The Bible and it's teachings I can't believe.

The fear of death doesn't trouble me;

Pure happiness I will never see.

And up in Heaven I can never go,

Nor in the grave or Hell below.

So get your Bible and read with care;

You'll find my name recorded there.

This puzzle was written by a lady in California in

1890 in response to a gentlemen

in Philadelphia, who said that he would pay

$241,000.00 to anyone who could

write a puzzle that he could not solve. He failed to

do so, and paid the lady

$241,000.00 (a great sum at that time).

The answer is one word, five letters long, and

appears only four times in the King

James Version of the Bible.

the answer to this riddle is below---

WHALE

This riddle pertains to three houses and three utilities. The object is to connect all

three utilities to each house without the utilities crossing one another.

HOUSE A HOUSE B HOUSE C

WATER ELECTRICITY GAS

Again connect water to all three houses

Connect electricity to all three houses

Connect Gas to all three houses

But the catch is that none can cross each other when going to the houses.

Here's a couple of riddles 4 ya...

# 1-- A cowboy arrives into town on Sunday. He stays for 3 days and then leaves on Sunday. How is that possible?

#1 Answer: The horse's name is Sunday.

#2-- A man and his son gets into a car accident on their way home from a basketball game. The father is killed instantly. The son, however, survives and is in critical condition. When the nurse calls for the surgeon, the surgeon enters and replies, " I cannot operate on this boy, he's my son."

How is that possible?

#2 Answer: The surgeon happens to be the boy's mother.

Dear Friends,

Here's another more abstract riddle. Actually, this riddle requires only a yes/no response for clues. Here goes:

A man jumps from a 20 story building. As he jumps, he hears a telephone ring and wishes he hadn't jumped. Why?

Answer follows:

(The teller must answer questions with yes or no knowing that the answer is:

The man thinks he is the last person on earth. He feels there's no reason to live so he jumps from a building, and he hears a phone ring...

quite possibly another human!!)

Incidentally, this riddle has a Twilight Zone appeal to it.

Riddle:

Poor people have it,

Rich people need it,

It is better than God,

More evil than Satan,

If you eat it you will die.

answer below-

nothing

your left side is your right side,

your right side is your wrong side.

the right side,for your back side is the front side.

what is it??????????

Form one word from "NEW DOOR"???

CROSSER#1:

MATERIAL:

-there's 11 (yes, eleven) guys ready to cross a bridge

-they have 2 flashlights

-times to cross: 5 10 15 20 30 30 35 45 50 55 65

(like, it takes one guy 5 minutes....slowest 65 minutes)

RULES:

-2 guys maximum per flashlight

-each flashlight must be in constant motion; this means that

once a flashlight starts "moving", it must move constantly

until everybody has crossed the bridge, and the moving must

be while crossing back and forth

-once a crosser or 2 crossers (double crosser?) leave one end

of the bridge, they must walk to the other end; no stopping

to rest or turning around allowed

-yes: the time it takes is the slowest of the double crossers

-the final crossings must terminate at the SAME time; that is,

both flashlights arrive on the other side at same time; this

rule does not apply at other times: you're welcome

-no swapping (as in next puzzle) allowed

-everything is integral; no fractional nothing

-the two "30" guys hate each other and so do not cross together

-final rule: this is done in the minimum possible time

OK:

1-what is the minimum time in minutes?

2-for how many minutes does the "5" guy travel?

SOLUTION:

Examples: > 55/65 means the "55" and "65" guys cross

< 5/10 means the "5" and "10" guys come back

10(A) means switch in Flashlight

Flashlight#1:

0- 65: > 55/65 "5"guy

65- 75: < 10 10(A)

5(B) 75- 85: > 5/10 10(C) 10

85- 90: < 5 5

90-120: > 5/30 30

5(D) 120-125: < 5 5

125-155: > 20/30

Flashlight#2:

0- 10: > 5/10 10(A) 10

10- 15: < 5 5

15- 65: > 5/50 50

5(B) 65- 70: < 5 5

70-115: > 35/45

115-125: < 10 10(C)

5(D) 125-140: > 5/15 15

140-145: < 5 5

145-155: > 5/10 10

===

150 Note: may be done in a different "order; but 155 and 150 CAN'T be beat!!

CROSSER#2:

MATERIAL:

-there's 5 guys (A B C D E) ready to cross a bridge

-bridge is 2400 miles long

-at other end of bridge is a skate board (SB)

-this SB has a little headlight, with power for 1200 hours

-there are also 2 flashlights (F1 and F2)

-F1 has power for 1500 hours, F2 for 1800 hours

-hours to cross: A=600 B=900 C=1200 D=1200 E=2400

(like, it takes A 600 hours....slowest E 2400 hours)

note: if you feel sorry for the guys, you may change my

mile/hour cruelty to foot/second.

RULES:

-2 guys maximum per flashlight

-each flashlight must be in constant motion; this means that

once a flashlight starts "moving", it must move constantly

until everybody has crossed the bridge, and the moving must

be while crossing back and forth

-this rule does not apply to the SB

-once a crosser or 2 crossers (double crosser?) leave one end

of the bridge, they must walk to the other end; no stopping

to rest or turning around allowed

-turning around is also not allowed om the SB

-yes: the time it takes is the slowest of the double crossers

-when a guy hops on the SB, the SB's speed becomes twice that

of the guy (no: I don't have a good reason for that)

-the SB's headlight permits vision for the rider only; so if

a guy is crossing on the SB, he's all by his lonely

-the final crossings must terminate at the SAME time, plus the

5 guys must also arrive at the SAME time

-in other words, F1 F2 SB and the 5 guys arrive at SAME time;

this rule does not apply at other times: you're welcome

-good news: swapping is permitted on the bridge; as example,

if guy on SB "catches up" to a walking pair, he may become a

walker with one of the pair, while the other hops on the SB

-similarly, if a pair catches up with a pair, 2 guys can

swap "teams" or teams may swap flashlights

-"catches up" and "when they meet" is same thing rulewise

-all swappings take no time; plus swapping is a "shoulder to

shoulder" thing: no flashlight throwing!

-the rule "at speed of slowest" applies after swappings

-wrong! every swapper MUST continue in same direction

as before the swap; sorry bout that

-everything is integral; no fractional nothing

-final rule: this is done in the minimum possible time

OK:

1- what is the minimum time in hours?

2- what is total travelling time of SB?

3- which 2 guys terminate with F2?

SOLUTION:

Example: > A/F1 means A crosses using Flashlight#1

(F1=900) means Flashlight#1 has 900 hours left.

0- 600: > A/F1 (F1=900)

SB(300) 600- 900: < A/SB(F1) (SB=900)

900-1800: > A/B/F1 (F1=0)

0-1200: > D/E/F2 (F2=600) [to midpoint]

SB(300) 900-1200: > C/SB (SB=600) [to midpoint] C and E switch

1200-1800: > C/D/F2 (F2=0) [C and D arrive with F2]

SB(600) 1200-1800: > E/SB (SB=0)

SB total: 1200; everybody arrives at 1800; C and D with F2.

Here's more from Denis:

THE BORRIS RIVER CROSSERS

Note: I made up these 3 puzzles after solving the 2 "old" river-crossing puzzles (both invented by the famous puzzler Henry Dudeney), where 5 couples with jealous husbands cross a river in a boat that takes limit of 3 passengers, solution being "least one-way crossings": 1- anybody can drive boat (answer: 11 one-way crossings) 2- only one wife can drive boat (answer: 13 one-way crossings)

My puzzles involve "time" using different rowing speeds for husbands and wives, and solution is not the least number of crossings, but the shortest possible time.

BORRIS RIVER CROSSER 1

Five married couples need to cross a river; all they have

is a row boat: capacity of 3 passengers; all 3 can row:

I've arranged for 3 rowing seats just for this puzzle.

The guys each row at 15 mph, the gals at 5 mph; like, a guy and

his wife can row at 20 mph, 2 guys at 30 mph, 3 gals at 15 mph....

You guessed it: the guys are terribly jealous and insist on always

having their wives by their sides; so a wife is always with her

husband, on either side of the river or in the boat, if there is

another guy around. Wives may be by themselves, like you can have

3 wives all by themselves on one side of the river.

Out of the 10, 3 only know the directions to cross the river

(it's MY puzzle, so no comments!), so at least one of these 3

needs to be in the boat during each crossing.

Which 3? Sorry, I forgot; you decide.

What is the least time required to get everybody across?

Answer in minutes, as a reduced fraction if need be.

News Bulletin: the river is 30 miles wide!

Clarification: everybody gets out of the boat after each

one-way crossing.

SOLUTION:

Make the 5 couples Aa Bb Cc Dd Ee (capitals are husbands);

The 3 that know the directions: a b C

START SIDE BOAT OTHER SIDE SPEED MINUTES

1) AaBb DdEe Cc Cc 20 90

2) AaBbC DdEe C c 15 120

3) AaBb Ee CDd CcDd 35 360/7

4) AaBbC D Ee CD c d 30 60

5) A B C D E abe a b c d e 15 120

6) AaB C D Ee ae b c d 10 180

7) Aa Ee BCD BbCcDd 45 40

8) Aa Cc Ee Cc Bb Dd 20 90

9) a c e ACE A BbC DdE 45 40

10) a b c d e bd A B C D E 10 180

11) c e abd AaBbC DdE 15 120

12) Cc Ee CE AaBb Dd 30 60

13) c CEe AaBbC DdEe 35 360/7

14) Cc C AaBb DdEe 15 120

15) Cc AaBbCcDdEe 20 90

======

Total time: 9890/7

As you can see; the "trick" is to send as many as possible to do the "pick-ups", and to send the husbands as often as possible, since they row faster; number of one-way crossings is of no importance. The standard "least trips" solution (11) would take longer than this 15-trip solution.

BORRIS RIVER CROSSER 2

Very same as the 1st one, except this rule is slightly changed;

FROM:

Out of the 10, 3 only know the directions to cross the river

(it's MY puzzle, so no comments!), so at least one of these 3

needs to be in the boat during each crossing.

TO:

Out of the 10, 3 only know the directions to cross the river,

2 husbands and 1 wife, so at least one of these 3 needs to be

in the boat during each crossing.

What is the least time required to get everybody across?

Answer in minutes, as a reduced fraction if need be.

SOLUTION:

Make the 5 couples Aa Bb Cc Dd Ee (capitals are husbands);

The 3 that know the directions: A B e

START SIDE BOAT OTHER SIDE SPEED MINUTES

1) BbCcDdEe Aa Aa 20 90

2) A BbCcDdEe A a 15 120

3) CcDdEe ABb AaBb 35 360/7

4) A B CcDdEe AB a b 30 60

5) A B C D E cde a b c d e 15 120

6) A B C DdEe de a b c 10 180

7) DdEe ABC AaBbCc 45 40

8) CcDdEe Cc AaBb 20 90

9) CcDd Ee AaBb Ee 20 90

10) BbCcDd Bb Aa Ee 20 90

11) b c d BCD AaB C D Ee 45 40

12) a b c d e ae A B C D E 10 180

13) a b cde A B CcDdEe 15 120

14) AaBb AB CcDdEe 30 60

15) a ABb A BbCcDdEe 35 360/7

16) Aa A BbCcDdEe 15 120

17) Aa AaBbCcDdEe 20 90

=======

Total time: 11150/7

As you can see; the "trick" is to send as many as possible to do the "pick-ups", and to send the husbands as often as possible, since they row faster; number of one-way crossings is of no importance. The standard "least trips" solution (13) would take longer than this 17-trip solution.

BORRIS SPECIAL RIVER CROSSER

This time we got 6 couples:

Aa Bb Cc Dd Ee Ff (Capitals = husbands).

Jealousy rules are the same, except:

F hates his wife and doesn't care which guy(s) she's with;

well, they really can't stand each other and don't want to be

in the boat at same time;

or don't want to be on same river bank while boat crosses.

F : I hate your guts, f !

f : I shudda listened to mudder and never marry ya, ya jerk !!

...plus lots of other such non-jealous conversation.

(You may be interested to know that during my research for this

puzzle, I found out that F doubled the life insurance on f).

Oh yes; there is a slight change in the boating; still 3 maximum,

but special boating license is required; only one of the husbands

has one; sorry, forgot which husband.

Of the wives, only f has one: she just finished the boating course

and has been issued a temporary license: good for 4 one-way

crossings only.

So, when boat is crossing, f and/or that liscenced husband must

be in the boat.

What is the minimum number of one-way trips required to get

everybody across, and, if the guys each weigh 150 and the

gals each weigh 100 (except f who weighs a whopping 300 !),

how much weight "entered" the boat?

SOLUTION:

Drivers are A and f (driver in 1st spot)

START SIDE BOAT OTHER SIDE WEIGHT

1) BbCcDdEeF Aaf Aa f 550

2) A BbCcDdEeF A a f 150

3) CcDdEeF ABb AaBb f 400

4) CcDdEeFf f AaBb 300

5) DdEeF fCc AaBbCc f 550

6) DdEeFf f AaBbCc 300

7) EeF fDd AaBbCcDd f 550

8) Aa EeFf Aaf BbCcDd 550

9) a e f AEF A BbCcDdE F 450

10) Aa Ee f AE BbCcDd F 300

11) a f AEe A BbCcDdEeF 400

12) Aa f A BbCcDdEeF 150

13) Aaf AaBbCcDdEeFf 550

====

Total weight: 5200

What has 4 legs in the morning and 2 in the afternoon and three at night?

There was a man walking on a sandy desert and every time he looked behind him, he didn't see any footprints; there were no strong winds on that day. Explain.

what can you hold but not touch

Who, or what, is, or are Jane and Joseph? They are blue, they are orange.
They aren't green, what are they? Words that end in vowels

I am the originator of the "GRY" riddle
True, Language is the third word in the phrase "the English language",
but that is not the answer to the original riddle .
You have some typos on your solution page but here is the solution to the
GRY riddle.

The trick to this riddle is it was designed to be read aloud. The trick
is the usage of GRY vs. G or Y (pronounced G R Y) Now you should be able
to figure out the answer

"Think of words ending in -GRY. Angry and hungry are two of them. There
are three words people say in the English language that end in G "or" Y.
What is the third word? The word is something that everyone will say every
day. If you listen carefully to what I say , I have already told you the
answer three times."

OK. Well I got this riddle from a friend and i thought it was a good one.
here goes.

There is this guy that lives in a lighthouse. He wakes up feeling great
and very cheery. So he goes into the kitchen and then eats breakfast. He
picks up the paper and starts to read it. He reads something about his
lighthouse and the looks outside. He screams and then commits suicide. Why
did he do that?

The answer is that he forgot to turn on the light to the lighthouse and
all of the boats coming through crashed into the shore and he felt really
bad so he killed himself.

why is number six afraid of number seven???? because......seven ate (eight) nine!!!!!!

what is light as a feather, you can see it by the naked eye and if you put it in a barrel it would make the berrel lighter .....the answer is a hole